If A*B=6
A=3units
B=4units
Then the angle b/w A and B is
A.0
B.60
C.90
D.30
How to know what would be the value. Need understandable explantion to this ?
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given that, value of A cross product B=6
magnitude of Vector A=3 units
magnitude of Vector B= 4 units
now,
A × B = A.B. sinX , where X is the angle b/w A and B
6= 3.4. sinX
sinX= 1/2
X= 30°
so the answer is 30°
magnitude of Vector A=3 units
magnitude of Vector B= 4 units
now,
A × B = A.B. sinX , where X is the angle b/w A and B
6= 3.4. sinX
sinX= 1/2
X= 30°
so the answer is 30°
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