If a+b=6, ab=7, what is the value of a^2b+ab^2
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Answer:
the correct answer to this question is 42
explanation
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Given:
- a+b=6
=> a= 6-b
- ab=7
= a²b + ab²
= (6-b)b + 7²
= 6b - b² + 49
= -b²+6b +49
b² - 6b - 49 = 0 (taking out minus common)
then factorize using quadratic formula (D = b²-4ac)
HOPE THIS HELPS..!!
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