Question

if a+b=6 and a-b = 4/√2 then find 3/6

Answer 1

tep-by-step explanation:

Given

a-b = 4

=> a = 4+b ----(1)

and

a+b=6 ----(2)

Substitute (1) in equation (2), we get

=> 4+b+b=6

=> 4+2b=6

=> 2b=6-4

=> 2b=2

\implies b = \frac{2}{2}⟹b=22

\implies b = 1⟹b=1

Now ,

put b = 1 in equation (1), we get

a=4+1

=> a = 5

\begin{gathered} Value\: of\: a^{2}+b^{2}\\=5^{2}+1^{2}\\=25+1\\=26\end{gathered}Valueofa2+b2=52+12=25+1=26

Therefore,

The\: value\:of \:a^{2}+b^{2}=26Thevalueofa2+b2=26

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