Question

If a - b = 6 and a + b2 = 42, find the value of ab.​

Answer 1

Answer:

72

Step-by-step explanation:

a - b    = 6

a + b^2=42

then

b^2 + b = 36

b(b+1)=36

b = 6

a = 12

ab = 72

Answer 2

Answer:

ab=(+216)

Step-by-step explanation:

Given Question :

a - b = 6 and a + 2b = 42,

To find : the value of ab.​

Solution :

Let the first equation be,

a - b = 6 ----------------------(1)

Let the second equation be,

a + 2b = 42--------------------(2)

By subtracting equation (2) from (1) we get,

(a-a) -b-(2b) = 6-42

-b-2b = (-36)

-3b = (-36)

b=(-36)/(-3)

b=(+12)

By substituting the value of 'b' in equation (1) we get ,

a-b=6

a-(12)=6

a-12=6

a=6+12

a=(+18)

As we have to found the value of 'a' and 'b', we have to substitute the value of 'a' and 'b' in 'ab'.

Thus, by substituting the values we get,

ab=(+18)×(+12)

ab=(+216)

Ans : If a - b = 6 and a + b2 = 42, then the value of ab is (+216)