If a-b=6 and a2 +b2 =42,find the value of ab.
Answers
Answered by
1
Answer:
3
Step-by-step explanation:
a-b=6
(a-b)^2=a^2-2ab+b^2=6^2=36
a^2-b^2=42
=>42-2ab=36
=>2ab=42-36=6
=>ab=6/2=3
Answered by
1
the value of a-b =6
and the value of A2+b2=42
(a-b)2 = A2+b2-2ab
(6)2 = 42 -2ab
36 = 42-2ab
36-42= -2ab
-6= -2ab
ab = -6÷-2
ab =3
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