if a-b =6 and a2+b2=42, find the value of ab.
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Answered by
28
( a - b ) = 6
( a - b )^2 = 6^2
a^2 + b^2 - 2ab = 36
As given a^2 + b^2 = 42
42 - 2ab = 36
- 2ab = 36 - 42
ab = - 6 / - 2 or 3
Hope it helps
Answered by
13
The value of ab is 3.
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