If a-b=6 and ab=20, find the value of a³-b³.
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Answered by
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Given : a - b = 6 and ab = 20
On Cubing a - b = 6 both sides, we get :
(a - b)³ = (6)³
By Using an identity : (a - b)³ = a³ - b³ - 3ab(a - b)
(a)³– (b)³ – 3 ab (a – b) = 216
a³ - b³ – 3 × 20 (6) = 216
[a - b = 6 and ab = 20]
a³ - b³ - 360 = 216
a³ - b³ = 216 + 260
a³ - b³ = 576
Hence, the value of a³ - b³ is 576.
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If a-b=4 and ab=21, find the value of a³-b³.
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If a-b=-8, and ab =-12, then a³ – b³ =
A. -244
B. -240
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Answered by
1
Answer:
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Step-by-step explanation:
given a-b=6, ab=20
a^3-b^3
=>(a^2+b^2+a*b) (a-b)
=>((a-b)^2+2*ab +a*b) (a-b)
=>((a-b)^2+3*ab) (a-b)
=>6(36 +3(20))
=>6*96
=576
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