if a=b=60°,prove that tan(a-b)=tan a-tan b/1+tan a.tan b
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1
solve further u will get your answer
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Answered by
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LHS=tan(a-b)=tan(60-60)=tan0=0
RHS=tan a-tan b/(1-tan a.tan b)
=tan60-tan60/(""")
=0/(""")
=0
so, LHS=RHS(proved)
RHS=tan a-tan b/(1-tan a.tan b)
=tan60-tan60/(""")
=0/(""")
=0
so, LHS=RHS(proved)
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