if A+B=60° then prove that sin(120°-A)=cos(30°-B)
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A+B=60°
A=60°-B
sin (120°-60+B)=sin (90°-30°+B)
sin (60°+B)=sin (60°+B)
which is true
so,
Hence proved
HOPE IT HELPS
THANK YOU.
A=60°-B
sin (120°-60+B)=sin (90°-30°+B)
sin (60°+B)=sin (60°+B)
which is true
so,
Hence proved
HOPE IT HELPS
THANK YOU.
shibacharan:
we dont understand
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