Question

if a/b = 7/3, then find the value of 5a²+3b³/5a²-3b²


Tell me fast please​

Answer 1

Answer:

Given a+b = 5 & ab = 6

(a+b) 3 =a 3 +b 3 +3ab(a+b)5) 3 =a 3+b 3 +3×6[5]

125=a 3 +b 3 +90a 3+b 3 = 35

Answer 2

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Given,

$\frac{a}{b} = \frac{7}{3}$

To find the value of

$\frac{5 {a}^{2} + 3 {b}^{3} }{ {5a}^{2} - 3 {b}^{2} }$

$5 {a}^{2} + 3 {b}^{3} \\ 5 {( \frac{7}{3} })^{2} + 3 {( \frac{7}{3}) }^{3} \\ 5( \frac{49}{9} ) + 3( \frac{243}{27} ) \\ \frac{245}{9} + 27 = \frac{245 + 243}{9} \\ = \frac{488}{9}$

$5 {a}^{2} - 3 {b}^{2} \\ 5 {( \frac{7}{3}) }^{2} - 3 { (\frac{7}{3} })^{2} \\ 5( \frac{49}{9} ) - 3( \frac{49}{9} ) \\ \frac{245}{9} - \frac{147}{9} = \frac{245 - 147}{9} = \frac{98}{9}$

Sub the values ,we found

$\frac{ \frac{488}{9} }{ \frac{98}{9} } = \frac{488}{9} \div \frac{98}{9} \\ = \frac{488}{9} \times \frac{9}{98} = \frac{244}{49}$

Hope this will be helpful.