Question

If a/b = 7/3 then find the values of the following ratio.
$\frac{2a {}^{2} + 3b {}^{2} }{2a {}^{2} -3b {}^{2} }$
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Answer 1

Answer:

$\frac{a}{b} = \frac{7}{3} \\ a = 7 \\ b = 3 \\ \\ \frac{2 {a}^{2} + 3 {b}^{2} }{2 {a}^{2} - 3 {b}^{2} } \\ = \frac{2 {(7)}^{2} + 3 {(3)}^{2} }{2 {(7)}^{2} - 3 {(3)}^{2}} \\ = \frac{(2 \times 49) - (3 \times 9)}{(2 \times 49) - (3 \times 9)} \\ = \frac{98 + 27}{98 - 27} \\ \boxed{ = \underline{ \underline{ \frac{125}{71} }}}$

Answer 2

Answer:

$= \frac{125}{71}$

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