Math, asked by 201354, 1 year ago

IF a:b=7:8 and b:c=9;10 find a:b:c.
please answer this question right now​

Answers

Answered by ShiffaBDMI
1

Answer:

a:b=7:8 & b:c=9:10

a:b=63:72

b:c=72:80

Therefore, a:b:c=49:72:80.

Answered by TheLostMonk
2

Answer:

63 : 72 : 80 ........MB

Step-by-step explanation:

a /b = 7/8 --(1) , b /C = 9/10 --(2)

a/c = 7/8 * 9/10 = 63/80

a = 63c/80, from (2) b = 9c/10

a : b : c

= 63c/80 : 9c/10 : c

= 63/80 : 9/10 : 1

L.C.M (80,10) = 80

= 63×80/80 : 9×80/10 : 80 = 63 : 72 : 80

Or

7: 8

9 : 10

a : b : c=7×9 : 8 × 9 : 8 × 10= 63 : 72 : 80

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