If a-b =7, ab=8, find a²+b²
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If a-b = 7 and ab=8, then what is a^2+b^2?
a-b = 7 then
a = 7+b —————— (1)
ab=8 then
putting ‘a’ value as above
7+b (b) = 8
7+b^2 = 8 then b^2 = 8–7 which means, b^2 = 1 ————— (2)
Now apply this to a^2+b^2
Let’s imagine a^2+b^2 = 0 then,
a^2+1 = 0 [applying the value of (1) for b^2] then,
a^2 = -1 ———————- (3)
Now we have values of a^2 and b^2, lets apply to a^2+b^2
(-1) + 1 = 0
Hence , a^2+b^2 = 0
Step-by-step explanation:
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Step-by-step explanation:
keep first and second equations as 1 and 2 u will get a=8 and b= 1 there fore answer is 65
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