Math, asked by ysingh6067, 11 months ago

If a-b=7 ab=9 then what is the value of a^2-b^2

Answers

Answered by shadowsabers03
1

\longrightarrow\sf{a^2-b^2=(a+b)(a-b)}

\longrightarrow\sf{a^2-b^2=7\sqrt{(a+b)^2}}

\longrightarrow\sf{a^2-b^2=7\sqrt{a^2+2ab+b^2}}

\longrightarrow\sf{a^2-b^2=7\sqrt{a^2-2ab+b^2+4ab}}

\longrightarrow\sf{a^2-b^2=7\sqrt{(a-b)^2+4ab}}

\longrightarrow\sf{a^2-b^2=7\sqrt{7^2+4\times9}}

\longrightarrow\sf{a^2-b^2=7\sqrt{49+36}}

\longrightarrow\sf{\underline {\underline {a^2-b^2=7\sqrt{85}}}}

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