If a+b=7 & ab=10 so find value of a²+b²
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Answer:
, (a+b)=7, ab=10
Squaring both sides
⇒(a+b)2=72
⇒a2+b2+2ab=49
⇒a2+b2=49−2(10)
⇒a2+b2=29
Now,
(a−b)2=a2+b2−2ab
=29−2(10)
=29−20
=9
∴a−b=9
=±3
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