If (a-b)=7 and a^2+b^2=85,find a^3-b^3
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4
Answer:
721
Step-by-step explanation:
(a-b)=7
so
(a-b)²=7² [ squaring on both sides}
now expanding(a-b)²
a²+b²-2ab=49-----------(1)
we know a²+b²= 85---(2)
using 2 in 1
85-2ab=49
-2ab=-36
minus gets cancel both sides
2ab=36
ab=18-------3
now
a³-b³=(a-b)(a²+b²+ab)
substituting the values
a³-b³=(7)(85+18)
=721
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