If a-b=7 and a^3-b^3=133 then find ab and a square+b square
Answers
Answered by
47
Hey Mate ✌
Here's your answer,
Given : (a - b) = 7 ..............(1)
a³ - b³ = 133 .......................(2)
==> LHS = a³ - b³
==> a³ - b³ = ( a - b)( a² + ab + b²)
==> 133 = (a - b)( a² + ab + b²) ......from (2)
==> 133 = (7)(a² + ab + b²) ............from (1)
==> 133 / 7 = a² + ab + b²
==> 19 = a² + ab + b²
==> a² + ab + b² = 19
is the required answer ^_^
⭐ Hope you got your answer ⭐
Here's your answer,
Given : (a - b) = 7 ..............(1)
a³ - b³ = 133 .......................(2)
==> LHS = a³ - b³
==> a³ - b³ = ( a - b)( a² + ab + b²)
==> 133 = (a - b)( a² + ab + b²) ......from (2)
==> 133 = (7)(a² + ab + b²) ............from (1)
==> 133 / 7 = a² + ab + b²
==> 19 = a² + ab + b²
==> a² + ab + b² = 19
is the required answer ^_^
⭐ Hope you got your answer ⭐
Answered by
56
Answer:
a+b=7
a^3+b^3=133
a^2+b^2=?
(a+b)^2=a^2+b^2+2ab
(a+b)^3=a^3+b^3+3ab
7^3=133+3ab(a+b)
343-133=3ab(7)
210=3ab(7)
3ab=30
ab=10
therefore,
(a+b)^2=a^2+b^2+2ab
49=a^2+b^2+20
a^2+b^2=29
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