If a+b=7 and a^3+b^3=91, find the value of ab
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Answer:
given,
a + b = 7
and a³ + b³ = 91
since,
a³ + b³ = ( a + b)³ -3ab( a + b)
=> 91 = 7³ -3ab× 7
=> 91 = 343 - 21ab
=> 21ab = 343 -91
=> 21ab = 252
=> ab = 253/21 = 12
so,
ab = 12.
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