If a+ b=7 and a square + b square =29 find the value of a and b
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Step-by-step explanation:
given- a+b=7.....(1) and a²+b²=29
using identity- (a+b)²=a²+2ab+b², we get-
(7)²=29+2ab (substituting the given values)
49-29=2ab
20=2ab
10=ab......(2)
using(1) in (2) we get-
10=a(7-a)
10=7a-a²
=> a²-7a+10=0
now solving this equation-
a²-5a-2a+10=0
a(a-5) -2(a-5)=0
(a-5)(a-2)=0
a=5, 2
now, further solving-
case1-
when a=5
then,b=2
case2-
when a=2
then,b=5
hope it helps!
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