If a+b=7 and ab =12,find the value of apower4 minus bpower4
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Given, a+b =7, ab = 12
Therefore
ab =12
a=12/b
12/b + b = 7
12+b²=7b
b²-7b+12=0
b²-3b-4b+12=0
b(b-3) -4(b-3) =0
(b-4) (b-3) =0
b=4 or b =3
so, a is 3 or 4
So, a⁴-b⁴=(taking b=3) 81-256 =-175
taking b=4
256-81=+175
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