if a+b=7 and ab=12 find the values of a^3+b^3+c^3-3abc
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Step-by-step explanation:
a + b = 7
(Cubing both sides)
( a + b )^3 = 7^3
a3 + b3 + 3ab ( a+b)= 343
Put ab=12 and a + b = 7
a3 + b3 + 3 × 12 × 7 = 343
a3 + b3 + 252 = 343
a3 + b3 = 343 - 252
a3 + b3 = 91
Therefore... a3 + b3 = 91
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