Question

If a+b= 7 and ab= 12 then find the value of a-b





Give with explanations.......​

Answer 1

$\huge\bigstar\underline\mathfrak{Answer}$

$\boxed{-1}$ and $\boxed{1}$

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$\huge\bigstar\underline\mathfrak{Explanation}$

Given :

a+b=7

ab=12

To find :

Value of (a-b)=?

We know that,

(a+b)²=(a-b)²+4ab

Now, put the given values in it.

(7)²=(a-b)²+4(12)

49=(a-b)²+48

49-48=(a-b)²

(a-b)²=1

(a-b)=±1

Therefore, there are two values which are suitable, that is, -1 and 1.

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Answer 2

${\huge {\mathfrak {Answer :-}}}$

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Given,

a + b = 7 , ab = 12

We thus have,

$\implies$ (a + b)^2 = (a - b)^2 + 4ab

$\implies$ (7)^2 = (a - b)^2 + 4 × 12

$\implies$ 49 - 48 = (a - b)^2

$\implies$ (a - b)^2 = 1

$\implies$ (a - b) = +1, - 1

.°. The value of (a - b) is either 1 or ( -1).

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