Math, asked by grisu6677, 2 days ago

if (a-b)=7 and ab=4 find the value of a square+ b square

Answers

Answered by kavyagprathap
1

Answer:

57

Step-by-step explanation:

a-b=7

ab=4

(a-b)²=a²+b²-2ab

7² =a²+b²-2×4

49=a²+b²-8

49+8=a²+b²

ie,. a²+b²=57

Answered by kuhu001
0

Answer:

a- b = 7 , ab=4 , a ^2+b^2 = ?

(a - b)^2 = 49

a^2 + b^2 - 2ab = 49

a^2 +b^2 - 2x4 = 49

a^2 + b^2 - 8 = 49

a^2+ b ^2 = 49 + 8

a^2+ b^2 = 57

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