if (a-b)=7 and ab=4 find the value of a square+ b square
Answers
Answered by
1
Answer:
57
Step-by-step explanation:
a-b=7
ab=4
(a-b)²=a²+b²-2ab
7² =a²+b²-2×4
49=a²+b²-8
49+8=a²+b²
ie,. a²+b²=57
Answered by
0
Answer:
a- b = 7 , ab=4 , a ^2+b^2 = ?
(a - b)^2 = 49
a^2 + b^2 - 2ab = 49
a^2 +b^2 - 2x4 = 49
a^2 + b^2 - 8 = 49
a^2+ b ^2 = 49 + 8
a^2+ b^2 = 57
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