If a-b=7 and ab=9 then a2+b2=?
Answers
Answered by
130
Hlo
a- b = 7
ab = 9
(a - b )^2 = a^2 + b^2 - 2ab
( 7)^2 = a^2 + b^2 - 2 × 9
49 = a^2 + b^2 - 18
49 + 18 = a^2 + b^2
67 = a^2 + b^2
hope it helps.♥
a- b = 7
ab = 9
(a - b )^2 = a^2 + b^2 - 2ab
( 7)^2 = a^2 + b^2 - 2 × 9
49 = a^2 + b^2 - 18
49 + 18 = a^2 + b^2
67 = a^2 + b^2
hope it helps.♥
Answered by
21
Given:
a-b=7
ab=9
To find:
a²+b²
Solution:
We can find the solution in a few simple steps-
We know that the value of a²+b² can be found by using a property of (a-b)².
(a-b)² = a²+b²-2ab
On putting the values, we get
7²= a²+b² -2×9
49= a²+b² -18
49+18= a²+b²
a²+b² =67
Therefore, the value of a²+b² is 67.
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