Question

If a = b = -7, then the value of (a - b) (2a2 +4ab+ 9b2) please say the ans ​

Answer 1

ANSWER : -

$a = b = -7$

∴$(a-b)(2a^2+4ab+9b^2)$

$= (a-a)(2a^2+4a^2+9a^2)$

$= 0(15a^2)$

$= 0$

Answer 2

Step-by-step explanation:

ANSWER : -

a = b = -7a=b=−7

∴(a-b)(2a^2+4ab+9b^2)(a−b)(2a2+4ab+9b2)

= (a-a)(2a^2+4a^2+9a^2)=(a−a)(2a2+4a2+9a2)

\begin{gathered}= 0(15a^2)\\\end{gathered}=0(15a2)

= 0=0