If a - b = 7, then the value of a² + b² - 2ab - 1 is
Answers
Answered by
1
Answer:
a-b=7
Therefore
(a-b)^2=a^2-2ab+b2
a^2+b^2-2ab=(7)^2
a^2+b^2-2ab=49
subtracting one from both sides
a^2+b^2-2ab-1=48
Hope it helps
Answered by
0
Answer:
48
Step-by-step explanation:
See the picture
By squaring 1st on both sides
Substraction by 1 on both side
Attachments:
Similar questions