if (a+b)=73 and ab=65. Find the value of a2+b2
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Answer:
The value of a² + b² is 5199 when a + b = 73 and ab = 65.
Step-by-step explanation:
Given that :
➸ a + b = 73
➸ ab = 65
We know the algebraic identity :
➸ (a + b)² = a² + b² + 2ab
Now, let’s substitute the above values in the formula and find a² + b² :
➸ (a + b)² = a² + b² + 2ab
➸ ( 73 )² = a² + b² + 2 ( 65 )
➸ 5329 = a² + b² + 2 ( 65 )
➸ 5329 = a² + b² + 130
➸ 5329 – 130 = a² + b²
➸ 5199 = a² + b²
Therefore, the value of a² + b² is 5199.
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