if (a-b)=75 and ab=28 find the value of a²+b²
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0
Answer:
a^2+b^2=(a-b)^2+2ab
=75^2+2*28
=5625+56=5681
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9
______________
a²+b²
= (a-b)² + 2ab
= 75² + 2 × 28
= 5625 + 56
= 5681
______________
Hope it helps you mate ❤️☃️
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