if a+b=7and ab=4and find the value of a²+b²
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0
Answer:
a²+b²
(a+b)²-2ab
7²-2×4
49-8
41
Answered by
0
Step-by-step explanation:
(a+b)^2= a^2+b^2+2ab
given a + b=7 ,ab=4
(7)^2= a^2+b^2+ 2(4)
49=a^2+b^2 +8
41 = a^2+ b^2
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