Question

If (a + b) = 8 and ab = 12, find the value of a'- b'.
(Hint: (a - b) = (a + b)2 - 4ab)​

Answer 1

Given:

• (a + b) = 8
• ab = 12

To Find:

• the value of $(a-b)$

Hint: (a - b) = (a + b)² - 4ab

Solution:

$(a - b) = {(a + b)}^{2} - 4ab \\ = {8}^{2} - 4(12) \\ = 64 - 48 \\ = 16 \\ \boxed{ \sf (a - b) = 16}$

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