Question

If a- b = -8 and ab = -12 , then find
i) a + b2 ii) a - b​

Answer 1

Answer:

Step-by-step explanation:

a-b=8 ab=-12

(a-b)²= a²+b²+2ab

8²=a²+b²+2*(-12)

64+24=a²+b²

a²+b²=88

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Answer 2

$a - b = - 8 \\ o n \: squaring \: both \: sides \: we \: get \: \\ {(a - b)}^{2} = { (- 8 )}^{2} \\ {a}^{2} + {b}^{2} - 2ab = 64 \\ putting \: the \: value \: of \: ab \: we \: get \\ {a}^{2} + {b}^{2} - 2 \times - 12 = 64 \\ {a}^{2} + {b}^{2} = 64 + ( - 24) = 40$

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2 \times ab \\ now \: on \: putting \: the \: values \: we \: get \: \\ {(a + b)}^{2} \: = \: (40) + 2 \times - 12 \\ = 40 - 24 \\ = 16$