Question

If (a - b) = 8 and ab = 5, find a2 + b2​

Answer 1

(a-b)^2=8^2

a2+b2-2ab = 64

a2+b2 = 64 + 2ab

= 64 + 2×5

a2+b2=74

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Answer 2

The value of a²+b² is 74.

Given,

The value of (a-b) is 8 and the value of ab is 5.

To Find,

The value of a²+b².

Solution,

The given values are (a - b) = 8 and ab = 5.

Now, using the formula

(a-b)² = a²+b²-2ab

Now, substituting the values of (a-b) as 8 and ab as 5.

8² = a²+b²-2(5)

Solving this equation further

64 = a²+b²-10

a²+b² = 64+10

a²+b² =74

Hence, the value of a²+b² is 74.

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