if (A+B)=8 ( C-D)=6 (A+C)=13 (B+D)=8. Then find ABCD
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Answered by
1
a+b=8……….(1)
c-d=6……….(2)
a+c=13………(3)
b+d=8……….(4)
Now,
(3)-(1) => c-b=5…….(5)
(2)+(4)=> c+b=14……(6)
(5)+(6) => 2c=19 => c=19/2=9.5
Put this value of ‘c’ in (6)
b=14–9.5=4.5
Put ‘b’ in (1)
a=8–4.5=3.5
Put ‘b’ in (4)
d=8–4.5=3.5
The answers :-3.5,4.5,9.5,3.5
Answered by
1
a+b=8
b=8-a:eq1
c-d=6
c=6+d:eq2
a+c=13
a=13-c:eq3
b+d=8
b=8-d:eq4
by eq 1and 4
8-d=8-a
so a=d
acc to eq3
a=13-(6+d)
a=13-6-d
a=13-6-a
2a= 7
a=7/2
d=7/2
b=8-7/2
b=9/2
c=6+7/2
c=19/2
b=8-a:eq1
c-d=6
c=6+d:eq2
a+c=13
a=13-c:eq3
b+d=8
b=8-d:eq4
by eq 1and 4
8-d=8-a
so a=d
acc to eq3
a=13-(6+d)
a=13-6-d
a=13-6-a
2a= 7
a=7/2
d=7/2
b=8-7/2
b=9/2
c=6+7/2
c=19/2
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