if a+b=9 and a^2+b^2=51, find the value of ab
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Answered by
6
a+b=9
a^2+b^2=51
(a+b)^2-2ab=51
=9^2-2ab=51
2ab=81-51=30
ab=15
Answered by
2
Answer:
α + в = 9
4 + 5 = 9
α^2 + в^2 = 51
4^2 + 5^2 = 51
36 + 25 = 51
αв
4 * 5 = 20
ʋǟʟʊɛ օʄ ǟ ǟռɖ ɮ ɨֆ 20 .
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