If a + b =9 and a2+ b2=71, find a3+ b3
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Answer: a³ + b³= 594
Step-by-step explanation:
a + b = 9
a² + b² = 71
(a + b)² = a² + b² +2ab
(9)² = 71 + 2ab
81 = 71 + 2ab
10 = 2ab
ab = 5
a³ + b³ = (a+b)(a²+b²-ab)
= (9)(71 - 5)
= (9)(66)
a³ + b³= 594
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