Math, asked by ieshiloise, 10 months ago

if a-b=9 and ab=4, find the value of a^2+b^2

Answers

Answered by IlakkiyaK
0

Step-by-step explanation:

a+b=9

Squaring both the sides

=>a²+b²+2ab=81

Substituting value of 'ab' in equation

=>a²+b²+2*4=81

=>a²+b²=73

Answered by jtg07
6

Step-by-step explanation:

\huge\begin{lgathered}\frak\red{answEr}\end{lgathered}

\mathfrak\blue{given::}

➡️ a-b = 9

➡️ ab = 4

\mathfrak\orange{to find::}

➡️ a²+b²

_______________________________________

we know the following identity::

{(a  - b)}^{2}  =  {a}^{2}  +  {b}^{2}   - 2ab

replacing values,,

(a-b)²=a²+b²-2ab

➡️ (9)² = a²+b² - 2×4

➡️ 81 = a²+b²-8

➡️ a²+b² = 89

so,

89 is the final answer

hope this helps

@jtg07♥️♥️

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