Math, asked by palakpreet12096, 8 months ago

If a+b =9 and ab =5 , find the value of a square +b square ​

Answers

Answered by vikhyat04
4

Answer:

a²+b²=71

Step-by-step explanation:

Given a+b=9 ---(1)

ab = 5 ---(2)

On Squaring equation (1) , we get

(a+b)² = 9²

=> a²+b²+2ab=81

=> a²+b²+2×5=81 /*From (1)

=> a²+b²+10= 81

=> a²+b² = 81-10

=> a²+b² = 71

Therefore,

a²+b² = 71

Answered by nihalnn568
3

Answer:

a

a { }^{2}  + b {}^{2}  = 71

Step-by-step explanation:

Given a+b=9

By squaring both sides

(a+b)2=81

By expanding

a  {}^{2}  + 2ab + b {}^{2}  = 81

Give ab=5

2ab=10

Hence answer 81-10=71

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