Question

if A+B=90 and secA=4/3 find cosec B

Answer 1

Since Sec denominations are h/b

so h = 4 and b = 3 ie hypotanious and base consecutively.

from Pythagoras Theorem,

${h }^{2} = { p}^{2} + {b }^{2}$
so 4^2 = p^2 + 3^2

=> 16 = p^2 +9

=> p^2 = 7

so p =
$\sqrt{7}$
hence cosec B = h/p

= 4/
$4 \div \sqrt{7}$