If A+B = 90 and secA5/3 then find value of cosec b
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Given that,
A+B = 90 degree
Sec A = 5/3
So we can put
A = 90 - B
Thus putting in Sec A we get
Sec (90 - B) = 5/3
According to Trigonometry identity
we know,
Sec(90 - x) = Cosec x
Thus applying the same here, we get
Cosec B = 5/3
A+B = 90 degree
Sec A = 5/3
So we can put
A = 90 - B
Thus putting in Sec A we get
Sec (90 - B) = 5/3
According to Trigonometry identity
we know,
Sec(90 - x) = Cosec x
Thus applying the same here, we get
Cosec B = 5/3
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