If A+B= 90 degree and sac A = 5/3, then find the value of cosec B
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seca=5/3
cosa=3/5
sina=4/5
since a+b=90
sin(a+b)=1
sinacosb+cosasinb=1
(4/5)cosb+(3/5)sinb=1.........(1)
since b=90-a
cosb=cosa
cosb=3/5
put in (1)
(4/5)(3/5)+(3/5)(sinb) =1
find sin b from here and do reciprocal
cosa=3/5
sina=4/5
since a+b=90
sin(a+b)=1
sinacosb+cosasinb=1
(4/5)cosb+(3/5)sinb=1.........(1)
since b=90-a
cosb=cosa
cosb=3/5
put in (1)
(4/5)(3/5)+(3/5)(sinb) =1
find sin b from here and do reciprocal
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