Question

If A+B=90° and cosB=1/3; then the value of sinA is:​

Answer 1

Answer:

sinA=1/3

Step-by-step explanation:

A+B=90°

B=90°-A

Taking cos both sides

cosB=cos(90°-A)

1/3=sinA

[cos(90°-A)=sinA ]

Answer 2

The value of sin A is 1/3

Step-by-step explanation:

A+B=90°

B=90°-A

Taking cos both sides

cos B=cos(90°-A) ...(1)

given that

$\cos B = \frac{1}{3}$

put the value of cos in equation 1

$\frac{1}{3}= \sin A$

because cos (90-A ) = sin A

thus ,

The value of sin A is 1/3

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