If A +B =90° and sec A = 2⅔, then find the value of cosec B.
Answers
The value of cosec B is
The value of cosec B is 3
2
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA=
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 3
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 32
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 32We have to find the value of cosec B.
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 32We have to find the value of cosec B.As A+B=90°
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 32We have to find the value of cosec B.As A+B=90°⇒ A=90°-B
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 32We have to find the value of cosec B.As A+B=90°⇒ A=90°-Bsec A=\frac{2}{3}secA=
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 32We have to find the value of cosec B.As A+B=90°⇒ A=90°-Bsec A=\frac{2}{3}secA= 3
\text{Given that if }A+B=90^{\circ}\text{ and }sec A=\frac{2}{3}Given that if A+B=90 ∘ and secA= 32We have to find the value of cosec B.As A+B=90°⇒ A=90°-Bsec A=\frac{2}{3}secA= 32 sec(90^{\circ}-B)=\frac{2}{3}sec(90
sec(90^{\circ}-B)=\frac{2}{3}sec(90 ∘ −B)=
sec(90^{\circ}-B)=\frac{2}{3}sec(90 ∘ −B)= 3
sec(90^{\circ}-B)=\frac{2}{3}sec(90 ∘ −B)= 32
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθ
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθcosec B=\frac{2}{3}cosecB=
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθcosec B=\frac{2}{3}cosecB= 3
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθcosec B=\frac{2}{3}cosecB= 32
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθcosec B=\frac{2}{3}cosecB= 32\text{Hence, the value of cosec B is }\frac{2}{3}Hence, the value of cosec B is
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθcosec B=\frac{2}{3}cosecB= 32\text{Hence, the value of cosec B is }\frac{2}{3}Hence, the value of cosec B is 3
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθcosec B=\frac{2}{3}cosecB= 32\text{Hence, the value of cosec B is }\frac{2}{3}Hence, the value of cosec B is 32
\text{As }sec(90-\theta)=cosec \thetaAs sec(90−θ)=cosecθcosec B=\frac{2}{3}cosecB= 32\text{Hence, the value of cosec B is }\frac{2}{3}Hence, the value of cosec B is 32