Question

if A+B=90° and secA=4√3 find cosecB​

Answer 1

Answer:

hey mate this is your answer ...

Step-by-step explanation:

Since Sec denominations are h/b

so h = 4 and b = 3 ie hypotanious and base consecutively.

from Pythagoras Theorem,

{h }^{2} = { p}^{2} + {b }^{2}h

2

=p

2

+b

2

so 4^2 = p^2 + 3^2

=> 16 = p^2 +9

=> p^2 = 7

so p =

\sqrt{7}

7

hence cosec B = h/p

= 4/

4 \div \sqrt{7}4÷

7

plzz mark as brainliest ...