Question

If A+B=90° cosecA= 5/3 find sinAcosB-cosAsinB

Answer 1

Answer:

sinA× cos(90-B) + cosA×sin (90-B)×cosecA×sec(90-B) - cotA× cosec(90-B)× sinA / sec (90-B) + cos A / cosec (90-B) -3

=sinA × sinA + cosA × cosA × cosecA × cosecA - cotA × cotA × sinA /1÷sinA+ cosA / 1/÷cosA -3

=sinA square + cos A square × cosA square - cotA square × sinA square + cosA square -3

= 1×1×1-3

=1-3

= -2

Answer 2

Answer:

a+b= 90°

a= 5/3

a+b= 5/3

90°= 5/3

90°×3/5 = a

54°= a

a= 54°

so, a+b= 90°

54°+b= 90°

90°-54°= 36°

b= 36°