Question

If A + B = 90°, cotB= 3/4 then find the value of tanA

Answer 1

Answer:

it is 3/4

be blessed☺

cotB=3/4 therefore tanB=4/3

so tanA=3/4

Answer 2

Answer:

Required value of tanA is $\frac{3}{4}$

Step-by-step explanation:

Given,cotB=$\frac{3}{4}$

and A+B=90°

This is a problem of Trigonometry.

We know,

$\tan(x) = \cot(\frac{\pi}{2} - x)$

If we know value of x then we can solve this easily.

For example,

Let $\cot(x) = \frac{1}{2}$

and $x + y = {90}^{o}$

So,

$x= {90}^{o} - y$

Therefore,

$\cot(x) = \cot( {90}^{o} - y) = \tan(y)$

Now,

$\cot(x) = \tan(y) = \frac{1}{2}$

Here given,cotB$= \frac{3}{4}$

Now,A+B=90°

So, B=90°-A

Therefore,

$\cot(B) = \cot( {90}^{o} -A ) = \tan(A) = \frac{3}{4}$

Required value of tanA is $\frac{3}{4}$

Important formulas of related this chapter:

$sin(x) = \cos(\frac{\pi}{2} - x) \\ \tan(x) = \cot(\frac{\pi}{2} - x) \\ \sec(x) = \csc(\frac{\pi}{2} - x) \\ \cos(x) = \sin(\frac{\pi}{2} - x) \\ \cot(x) = \tan(\frac{\pi}{2} - x) \\ \csc(x) = \sec(\frac{\pi}{2} - x)$