Question

if A+B=90° prove cosA/sinB-cosAsinB=sin2 A​

Answer 1

Answer:

Given that A + B = 90 degrees, show that root cosA cosecB-cosAsinB = sin A. ... Show by vector method that sin2A=2sinAcos A. ... If cosA+cos^(2)A=1, then prove that sin

Take a = 90 and b= 45 to verify that: sin(a-b)=sinacosb-cosasinb,cos(a-b )=cosa cosb

If a and B Are Complementary Angles, Prove That: Cota Cotb - Sina Cosb - Cosasinb = 0 Concept: ... cotA cot(90° - A) - sinA cos(90° - A) - cosA sin(90° - A) ... 1 - (sin2A + cos2A). = 1 - 1.

Given that a+b=90° show that √cosa cosecb-cos a sin b = sin a ... root CosA cosec(90-A) - cosAsin(90-A) ... a man

sinA=cosB

sinA=sin(90−B)

A=90−B

A+B=90

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