if A+B=90° prove that secA cosecB-tanA cotB=1 and sec2A-cot2B=1
Answers
Answered by
1
ʜᴇʏᴀ!!
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
_____________________________
ɢɪᴠᴇɴ , ᴀ + ʙ = 90°
ᴏʀ , ᴀ = ( 90° - ʙ )
ɴᴏᴡ ,
1. sᴇᴄᴀ ᴄᴏsᴇᴄʙ-ᴛᴀɴᴀ ᴄᴏᴛʙ=1
ʟ.ʜ.s
• sᴇᴄᴀ ᴄᴏsᴇᴄʙ - ᴛᴀɴᴀ ᴄᴏᴛʙ
= sᴇᴄ ( 90° - ʙ ) ᴄᴏsᴇᴄʙ - ᴛᴀɴ ( 90° - ʙ ) ᴄᴏᴛʙ
= ᴄᴏsᴇᴄʙ ᴄᴏsᴇᴄʙ - ᴄᴏᴛʙ ᴄᴏᴛʙ
= ᴄᴏsᴇᴄ^2ʙ - ᴄᴏᴛ^2ʙ
= 1
ʀ.ʜ.s = 1
•°• ʟ.ʜ.s = ʀ.ʜ.s. [ ᴘʀᴏᴠᴇᴅ ]
________________________
2. sᴇᴄ2ᴀ-ᴄᴏᴛ2ʙ=1
ʟ.ʜ.s
• sᴇᴄ^2ᴀ - ᴄᴏᴛ^2ʙ
= sᴇᴄ^2 ( 90° - ʙ ) - ᴄᴏᴛ^2ʙ
= ᴄᴏsᴇᴄ^2ʙ - ᴄᴏᴛ^2ʙ
= 1
ʀ.ʜ.s = 1
sᴏ , ʟ.ʜ.s = ʀ.ʜ.s [ ᴘʀᴏᴠᴇᴅ ]
____________________________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ! :)
★ ᴅᴇᴠɪʟ ᴋɪɴɢ
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
_____________________________
ɢɪᴠᴇɴ , ᴀ + ʙ = 90°
ᴏʀ , ᴀ = ( 90° - ʙ )
ɴᴏᴡ ,
1. sᴇᴄᴀ ᴄᴏsᴇᴄʙ-ᴛᴀɴᴀ ᴄᴏᴛʙ=1
ʟ.ʜ.s
• sᴇᴄᴀ ᴄᴏsᴇᴄʙ - ᴛᴀɴᴀ ᴄᴏᴛʙ
= sᴇᴄ ( 90° - ʙ ) ᴄᴏsᴇᴄʙ - ᴛᴀɴ ( 90° - ʙ ) ᴄᴏᴛʙ
= ᴄᴏsᴇᴄʙ ᴄᴏsᴇᴄʙ - ᴄᴏᴛʙ ᴄᴏᴛʙ
= ᴄᴏsᴇᴄ^2ʙ - ᴄᴏᴛ^2ʙ
= 1
ʀ.ʜ.s = 1
•°• ʟ.ʜ.s = ʀ.ʜ.s. [ ᴘʀᴏᴠᴇᴅ ]
________________________
2. sᴇᴄ2ᴀ-ᴄᴏᴛ2ʙ=1
ʟ.ʜ.s
• sᴇᴄ^2ᴀ - ᴄᴏᴛ^2ʙ
= sᴇᴄ^2 ( 90° - ʙ ) - ᴄᴏᴛ^2ʙ
= ᴄᴏsᴇᴄ^2ʙ - ᴄᴏᴛ^2ʙ
= 1
ʀ.ʜ.s = 1
sᴏ , ʟ.ʜ.s = ʀ.ʜ.s [ ᴘʀᴏᴠᴇᴅ ]
____________________________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ! :)
★ ᴅᴇᴠɪʟ ᴋɪɴɢ
Similar questions
Math,
7 months ago
Science,
7 months ago
Math,
7 months ago
History,
1 year ago
Accountancy,
1 year ago
Accountancy,
1 year ago