If a + B = 90° , Prove that Seca Sinß + Cosa Cosecß = 2
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Given- a + b = 90 degree
LHS
root CosA cosec(90-A) - cosAsin(90-A)
root CosA secA - cosAcosA
root 1 - cos^2A
root Sin^2A
SinA = RHS
hence proved...PLEASE FOLLOW ME..PLEASE FOLLOW ME
Answered by
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Step-by-step explanation:
Given- a + b = 90 degree
LHS
root CosA cosec(90-A) - cosAsin(90-A)
root CosA secA - cosAcosA
root 1 - cos^2A
root Sin^2A
SinA = RHS
hence proved
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