Math, asked by piyush4993, 1 year ago

If A + B = 90°, show that
(1) sec^2A - cot^2B = 1
(2) secA cosec B - tan A cot B=1
(3) cosecA cos B + secA sinB = 2

plzzzzzzzz urgent​

Answers

Answered by dhiraj1659
0

Answer:

If A + B = 90°, show that

(1) sec^2A - cot^2B = 1

(2) secA cosec B - tan A cot B=1

(3) cosecA cos B + secA sinB = 2

plzzzzzzzz urgent


piyush4993: get lost
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