If A + B = 90°, sin A = a and sin B = b then prove a^2 + b^2 = 1
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Answered by
2
a^2 + b^2
sin^A + sin^B
sin^A + sin^(90-A)
sin^A + cos^B
=1
sin^A + sin^B
sin^A + sin^(90-A)
sin^A + cos^B
=1
Answered by
3
Given A+B=90°
sinA=a , Sin B=b
L.H.S =( SinA)^2 + (Sin B)^2
=
sinA=a , Sin B=b
L.H.S =( SinA)^2 + (Sin B)^2
=
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